SOLUTION: A train leaves Orlando at 1:00 PM. A second train leaves the same city in the same direction at 3:00 PM. The second train travels 32 mph faster than the first. If the second tra

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Question 950545: A train leaves Orlando at 1:00 PM. A second train leaves the same city in the same direction at 3:00 PM. The second train travels 32 mph faster than the first. If the second train overtakes the first at 7:00 PM, what is the speed of each of the two trains?

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = the speed in mi/hr of the 1st train
= the speed in mi/hr of the 2nd train
--------------------
From 1 PM to 3 PM is hrs
The 1st train's head start is:

--------------------
Start a stopwatch when the 2nd train leaves
at 3 PM and stop the watch at 7 PM
--------------------
Let = the distance the 2nd train travels
from 3 PM to 7 PM
--------------------
Equation for the 1st train:
(1)
Equation for the 2nd train:
(2)
---------------------
(1)
(1)
Plug this result into (2)
(2)
(2)
(2)
(2)
and

------------------
The speed of the 1st train is 64 mi/hr
The speed of the 2nd train is 96 mi/hr
check:
(1)
(1)
(1)
and
(2)
(2)
(2)
OK

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