SOLUTION: the tortoise and the hare have their long awaited rematch. the tortoise gets a 1000 foot lead and runs at 9 inches (.75ft) per second. the hare begins at the starting line and runs

Question 949850: the tortoise and the hare have their long awaited rematch. the tortoise gets a 1000 foot lead and runs at 9 inches (.75ft) per second. the hare begins at the starting line and runs at a rate of 6 ft per second. There is also a rat in the race, he starts at 1200 feet ahead of the hare and runs back towards the starting like at a rate of 2 feet per second.
Write an equation for each of the runners ,relating time t to distance from the starting line d.Also ,include an equation for both the one- minute mark and the finish line.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
the tortoise and the hare have their long awaited rematch.
the tortoise gets a 1000 foot lead and runs at 9 inches (.75ft) per second.
the hare begins at the starting line and runs at a rate of 6 ft per second. There is also a rat in the race, he starts at 1200 feet ahead of the hare and runs back towards the starting like at a rate of 2 feet per second.
Write an equation for each of the runners ,relating time t to distance from the starting line d. Also ,include an equation for both the one- minute mark and the finish line.
:
Tortoise: d = .75t + 1000, red
Hare: d = 6t, green
Rat: d = 1200 - 2t, blue
Finish line is purple at 1200 ft
:

:
1 minute mark: x = 60, a vertical line on the graph
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