SOLUTION: A freight train left Bangalore and traveled south. One hour later a passenger train left traveling 20 km/h faster in an effort to catch up to it. After three hours the passenger

Question 946314: A freight train left Bangalore and traveled south. One hour later a passenger train left traveling 20 km/h faster in an effort to catch up to it. After three hours the passenger train finally caught up. Find the freight train's average speed.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A freight train left Bangalore and traveled south. One hour later a passenger train left traveling 20 km/h faster in an effort to catch up to it. After three hours the passenger train finally caught up. Find the freight train's average speed.
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Passenger train DATA::
time = 3 hrs ; rate = x+20 km/hr ; distance = r*t = 3(x+20) km
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Freight train DATA:
time = 4 hrs ; rate = x km/hr ; distance = r*t = 4x km
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Equation:
distance = distance
4x = 3x+60
x = 60 km/hr (freight train rate)
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Cheers,
Stan H.
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