SOLUTION: at noon a plane left Austin for LA, 2100 miles away, flying 500km/hr. One hour later a jet left LA for Austin at 700 km/h. At what time die they pass each other.

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Question 94477This question is from textbook
: at noon a plane left Austin for LA, 2100 miles away, flying 500km/hr. One hour later a jet left LA for Austin at 700 km/h. At what time die they pass each other.This question is from textbook

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
500T+700(T-1)=2100
500T+700T-700=2100
1200T=2100+700
1200T=2800
T=2800/1200
T=2.3333 HOURS THEY WILL MEET.
PROOF
500*2.3333+700*1.3333=2100
1166.666+933.333=2100
2100=2100