SOLUTION: A privet plane traveled from Seattle to a rugged wilderness, at an average speed of 234mph. On the return trip the average speed was 273 mph. If the total traveling time was 8 hour

Question 943042: A privet plane traveled from Seattle to a rugged wilderness, at an average speed of 234mph. On the return trip the average speed was 273 mph. If the total traveling time was 8 hours, how far is Seattle from the wilderness?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39630) (Show Source): You can put this solution on YOUR website!
Interesting how you asked this same question again but with slightly different given values. We can generalize the analysis and solution.

ASSIGN VARIABLES
U, the speed for going to.
V, the speed for returning.
T, total time going and returning.
d, the one-way distance, unknown.

___________________rate_________time_________distance
GOING______________U____________(___)__________d
RETRNG_____________V____________(___)_________d
Total____________________________T

Fill-in the missing time cells.
___________________rate_________time_________distance
GOING______________U____________d/U__________d
RETRNG_____________V____________d/V_________d
Total____________________________T

Obvious equation is , with only ONE unknown variable, being d.

Answer by MathTherapy(10557) (Show Source): You can put this solution on YOUR website!

A privet plane traveled from Seattle to a rugged wilderness, at an average speed of 234mph. On the return trip the average speed was 273 mph. If the total traveling time was 8 hours, how far is Seattle from the wilderness?

Let distance be D
Then time taken on outbound journey =
Time taken on inbound journey:
Since round-trip travel time was 8 hours, we get:
7D + 6D = 13,104 -------- Multiplying by LCD, 1,638
13D = 13,104
D, or distance = , or miles
You can do the check!!
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