SOLUTION: Two cars leave towns 480 kilometers apart at the same time and travel toward each other. One car's rate is 14 kilometers per hour less than the other's. If they meet in 3

Question 942885: Two cars leave towns
480
kilometers apart at the same time and travel toward each other. One car's rate is
14
kilometers per hour less than the other's. If they meet in
3
hours, what is the rate of the slower car?
Found 2 solutions by lwsshak3, macston:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Two cars leave towns 480 kilometers apart at the same time and travel toward each other. One car'srate is 14 kilometers per hour less than the other's. If they meet in 3 hours, what is the rate of the slower car?
..
let x=rate of slower car
x+14=rate of faster car
Both cars are traveling toward each other at a rate=x+(14+x)=2x+14
travel time*rate=distance
3(2x+14)=480
6x+42=480
6x=452
x=73
what is the rate of the slower car? 73 km/hr
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
They traveled 480 km in three hours, so combined speed was 160 km/hr
One was 14 km/hr faster, so subtract 14: 160-14=146 km/hr divide by 2
146/2=73 km/hr for the slower vehicle and 73+14=87 km/hr for the faster.
The combined total of 160 km/hr would cover the 480 km in three hours.
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