SOLUTION: Khang and Hector live 88 miles apart in southeastern Missouri. They
decide to bicycle towards each other and meet somewhere in between.
Hectorʹs rate of speed is 60% of Khan
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-> SOLUTION: Khang and Hector live 88 miles apart in southeastern Missouri. They
decide to bicycle towards each other and meet somewhere in between.
Hectorʹs rate of speed is 60% of Khan
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Question 941231: Khang and Hector live 88 miles apart in southeastern Missouri. They
decide to bicycle towards each other and meet somewhere in between.
Hectorʹs rate of speed is 60% of Khangʹs. They start out at the same time
and meet 5 hours later. Find Hectorʹs rate of speed. Found 2 solutions by lwsshak3, josmiceli:Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Khang and Hector live 88 miles apart in southeastern Missouri. They
decide to bicycle towards each other and meet somewhere in between.
Hectorʹs rate of speed is 60% of Khangʹs. They start out at the same time
and meet 5 hours later. Find Hectorʹs rate of speed.
***
let x=Kang's speed
0.6x=Hector's speed
speed at which Kang and Hector are bycycling toward each other=x+0.6x=1.6x
travel time =distance/speed
..
88/1.6x=5
8x=88
x=11
0.6x=6.6
Hectorʹs rate of speed=6.6 mph
You can put this solution on YOUR website! You can think of this as one person standing
still and the other moving at the sum of their
speeds
-------------------
Let = Khang's speed in mi/hr = Hector's speed in mi/hr
---------------------------------
Hector's speed is 6.6 mi/hr
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check:
Khang's equation:
(1)
(1) mi
---------------------
Hector's equation:
(2)
(2) mi
---------------------
OK
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