SOLUTION: Leah leaves work at 17:54, halfway home she meets her daughter who left home at 17:46. Knowing that Leah walks 1.5x faster than her daughter and that they are travelling in a strai
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Question 941053: Leah leaves work at 17:54, halfway home she meets her daughter who left home at 17:46. Knowing that Leah walks 1.5x faster than her daughter and that they are travelling in a straight line, at what time do they meet?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = the distance in feet from work to home
Find Leah's head start:
17:54 minus 17:46 = 8 min
Let = the daughter's walking speed in ft/min
= Leah's walking speed
ft
-----------------------
Start a stop watch when daughter leaves
add their speeds to find when they meet
minutes
---------------------
They meet at 17:46 + d/(2.5s) - 4.8
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