SOLUTION: Fred begins walking toward John's house at 3 mi/hr. John leaves his house at the same time and walks toward Fred's house on the same path at a rate of 2 mi/hr. How long will it be

Question 936762: Fred begins walking toward John's house at 3 mi/hr. John leaves his house at the same time and walks toward Fred's house on the same path at a rate of 2 mi/hr. How long will it be before they meet if the distance between the houses is 4 miles
Thanks for your help!

Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
s = d/t
t = d/s
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speed of fred and john relative to each other:
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s = 3 + 2
s = 5 mph
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t = 4/5
t = 0.8 hours * (60 min/hr)
t = 48 minutes
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