SOLUTION: Patty and Tom live 345 miles apart. they decide to drive to meet one another. Patty leaves at noon, traveling at an average rate of 45 mi/h, and Tom leaves at 3:00 pm traveling at

Question 935662: Patty and Tom live 345 miles apart. they decide to drive to meet one another. Patty leaves at noon, traveling at an average rate of 45 mi/h, and Tom leaves at 3:00 pm traveling at an average speed of 60 mi/h. At what time will they meet?
Found 2 solutions by josmiceli, TimothyLamb:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
How far does Patty get in the hours
before Toby leaves?

mi
-------------------
Start a stopwatch when Toby leaves
Let = time in hours on
stopwatch when they meet
Let = distance in miles that
Toby travels until they meet
-------------------------
Patty's equation:
(1)
Toby's equation:
(2)
----------------------
Substitute (2) into (1)
(1)
(1)
(1)
They will meet 2 hrs after Toby leaves
3 PM + 2 hrs = 5 PM
is when they meet
---------------------
check:
(2)
(2)
(2) mi
and
(1)
(1)
(1)
OK

Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
---
s = d/t
t = d/s
d = st
---
a = distance traveled by patty when tom departs:
a = 45*3
a = 135
---
b = distance between them when tom departs:
b = 345 - a
b = 345 - 135
b = 210
---
speed of patty and tom relative to each other:
s = 45 + 60
s = 105
---
time after tom departs when they meet:
t = d/s
t = 210/105
t = 2 hours
---
answer:
time when they meet:
3:00 pm + 2 hours = 5:00 pm
---
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