SOLUTION: A motorboat traveling with the current went 48 mi in 2 h. Traveling against the current, it took 3 h to travel the same distance. Find the rate of the boat in calm water and the ra
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Question 933794: A motorboat traveling with the current went 48 mi in 2 h. Traveling against the current, it took 3 h to travel the same distance. Find the rate of the boat in calm water and the rate of the current.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
boat speed =x mph
current speed =y mph
against current 3 hours
with current 2 hours
Distance against 48 miles distance with 48 miles
t=d/r against current -
48.00 / ( x - y )= 3.00
3.00 ( x - y ) = 2.00
3.00 x - 3.00 y = 48.00 ....................1
48.00 / ( x + y )= 2.00
2.00 ( x + y ) = 48.00
2.00 x + 2.00 y = 48.00 ...............2
Multiply (1) by 2.00
Multiply (2) by 3.00
we get
6.00 x + -6.00 y = 96.00
6.00 x + 6.00 y = 144.00
12.00 x = 240.00
/ 12.00
x = 20.00 mph
plug value of x in (1) y
3.00 x -3.00 y = 48.00
60.00 -3.00 -60.00 = 48.00
-3.00 y = 48.00
-3.00 y = -12.00 mph
y = 4.00
boat speed 20.00 mph
current speed 4.00 mph
m.ananth@hotmail.ca
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