SOLUTION: Two cyclists leave a city at the same time, one going east and the other going west. The west-bound cyclist bikes 4 mph faster than the east-bound cyclist. After 5 hours they are 2
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Question 932280: Two cyclists leave a city at the same time, one going east and the other going west. The west-bound cyclist bikes 4 mph faster than the east-bound cyclist. After 5 hours they are 200 miles apart. How fast is the east-bound cyclist going?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = speed east biker
y = speed west biker = x + 4
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relative speed of the bikers:
x + y
x + x + 4
2x + 4
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s = d/t
2x + 4 = 200/5
2x = 200/5 - 4
x = (200/5 - 4)/2
x = 18
y = x + 4
y = 18 + 4
y = 22
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answer:
x = speed east biker = 18 mph
y = speed west biker = 22 mph
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