SOLUTION: Michael swam 4 kilometers against the current in the same amount of time it took him to swim 16 kilometers with the current. The rate of the current was 3 kilometers per hour. How

Question 924335: Michael swam 4 kilometers against the current in the same amount of time it took him to swim 16 kilometers with the current. The rate of the current was 3 kilometers per hour. How fast would Michael swim if there were no current?
Having a really hard time setting up a solvable equation, could you help solve.
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = mike speed
y = current speed = 3 kph
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up stream:
x - y = 4/t
x = 4/t + y
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down stream:
x + y = 16/t
x = 16/t - y
---
x = 4/t + y
x = 16/t - y
4/t + y = 16/t - y
2y = 12/t
y = 6/t
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y = 3
y = 6/t
3 = 6/t
t = 2
---
x = 4/t + y
x = 4/t + 3
x = 4/2 + 3
x = 2 + 3
---
answer:
x = 5 mph
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