SOLUTION: I really need your help in solving this problem. I appreciate your time and efforts. Have a terrific evening :) Here is the question? Comparing travel. A plane can fly 300 miles

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Question 921359: I really need your help in solving this problem. I appreciate your time and efforts. Have a terrific evening :) Here is the question?
Comparing travel. A plane can fly 300 miles in the same time as it takes a car to go 120 miles. If the car travels 90 mph slower than the plane, find the speed of the plane?

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
RT=D rate time distance, basic rule for uniform rates of travel.

_____________rate__________time_________distance
PLANE_________r_____________t____________
CAR_________r-90____________t____________

This data table is filled to show two equations in the two unknowns, r and t, using RATE*TIME=DISTANCE. You need to perform the necessary algebraic steps to solve for r and t. You may need to use two substitutions, and you may find a quadratic equation resulting in the process.

Okay, I saw your latest message; but TRY solving the system. The process is simpler than I thought. No need for any quadratic in the process.


Do that solving properly and you should find ;
;
and .
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

I really need your help in solving this problem. I appreciate your time and efforts. Have a terrific evening :) Here is the question?
Comparing travel. A plane can fly 300 miles in the same time as it takes a car to go 120 miles. If the car travels 90 mph slower than the plane, find the speed of the plane?


Let speed of plane be S

Then speed of car = S – 90

 ----- Both cover respective distances in the same amount of time

300(S – 90) = 120(S) ------ Cross-multiplying

300S – 27,000 = 120S

300S – 120S = 27,000

180S = 27,000

S, or speed of plane = , or  mph 

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