SOLUTION: the time taken by a person to cover 150km was 2.5 hours more than the time taken in the return of the journey. if he returned at a speed of 10km per hour, more than the speed of go

Question 918081: the time taken by a person to cover 150km was 2.5 hours more than the time taken in the return of the journey. if he returned at a speed of 10km per hour, more than the speed of going , what was the speed per hour in each direction in km
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Forward speed x
return speed x + 10

Distance = same 150 miles 1
original time � time with increased speed = 2.5 hour
t=d/t

150 / x - 150 / ( x + 10 ) = 2.50
LCD= x ( x + 10 )
multiply by LCD
150 ( x + 10 ) - 150 x = 2.5 x ( x + 10 )
150 x + 1500 - 150 x = 2.5 X^2 + 25 x
1500 = 2.5 X^2 + 25 x
2.5 X^2 + 25 x - -1500 = 0
Find roots of the quadratic equation
a= 2.5 b= 25 c= -1500

x1= ( -25 + sqrt( 625 + 15000 )) / 5
x1=( -25 + 125 )/ 5
x1= 20

x2= ( -7 - sqrt( 49 - 20 ) / 2
x2=( -25 - 125 )/ 5
x2= -30
Ignore negative
forward speed = 20 kmph
return speed = 30 kmph
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