SOLUTION: Start from 110 feet away, a person on a bicycle rides toward a checkpoint and then passes it. The rider is traveling at a constant of 30m feet per second. The distance between the

Question 912620: Start from 110 feet away, a person on a bicycle rides toward a checkpoint and then passes it. The rider is traveling at a constant of 30m feet per second. The distance between the bicycle and the checkpoint is given by the equation d=(110-30t). At what times is the bike 40 feet away from the checkpoint?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Convert feet to meters
1 foot = 0.3048 meters
d = 110*0.3048 - 30t
|110*0.3048 - 30t| = 40
Solve for t (2 times, approaching & departing)
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