SOLUTION: tom travels 8 mi/hr. louis leaves 10 minute later from the same spot traveling at 18 mi/hr. how long will it take for louise to catch tom?
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Question 912107: tom travels 8 mi/hr. louis leaves 10 minute later from the same spot traveling at 18 mi/hr. how long will it take for louise to catch tom?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Gaining speed 18 -8= 10 mph
Headstart 8*0.16666667 =1.33333333 miles
Time to catch up 1.33333333/10=0.13333333 hours
Time to catch up =8 minutes
Algebraic solution
8(t+0.16666667)=18t
8t+1.33333333=18t
1.33333333=18t-8t
1.33333333=10t
t=0.13333333 hours
Distance to meeting 0.13333333*18=2.4 miles
code drtch1
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