SOLUTION: Two cyclists leave towns 75mi apart at the same time and travel toward each other. One cyclist travels 7mi/h slower than the other. If they meet in 3 hours, what is the rate of eac
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Question 909936: Two cyclists leave towns 75mi apart at the same time and travel toward each other. One cyclist travels 7mi/h slower than the other. If they meet in 3 hours, what is the rate of each cyclist?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
r faster rate
D = rt
3r + 3(r-7) = 75mi
6r = 96
r = 16mph, faster rate. slower speed is 9mph
and..checking
48mi + 27mi = 75mi
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