SOLUTION: After 4 minutes an ant traveled 105 meters and after 8 minutes the ant will have traveled 165 meters.
(a)
Assuming a linear equation can be used to model the change in distance
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Question 908916: After 4 minutes an ant traveled 105 meters and after 8 minutes the ant will have traveled 165 meters.
(a)
Assuming a linear equation can be used to model the change in distance traveled over time beetween 4 and 8 minutes, write this linear model in slope-intercept form: Switch to Equation Editor
Let ybe the distance traveled (in meters) after xminutes.
(b)
The significance of the slope in the context of this situation is:
The ant travels at an average of 45 minutes per meter.
The ant travels 45 meters in 15 minutes.
The ant travels at an average of 15 meters per minute.
The ant travels at an average of 45 meters per minute.
The ant travels at an average of 15 minutes per meter.
(c)
Predict the distance that the ant will have traveled after 16 minutes and the number of minutes it will take for the ant to travel 315 meters
The distance that the ant will have traveled after 16 minutes is meters.
(d)
The number of minutes that will pass from the time the ant begins moving until it has traveled 315 meters is minutes.
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
we are given two points, (4,105) and (8,165), then the slope m is
m = (165 - 105) / (8 - 4) = 60/4 = 15 and so far the equation looks likw
y = 15x + b
let's get the y intercept by substituting one of the points in the equation
105 = 15*4 + b
b = 45, therefore our linear equation is
y = 15x + 45
b) The ant travels at an average of 15 meters per minute.
c) y = 15*16 +45 = 285 meters
the distance the ant has traveled in 16 minutes is 285 meters
d) 315 = 15x + 45
x = 18 minutes
the ant has traveled 315 meters in 18 minutes
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