SOLUTION: A duck and a chicken are walking to school. One way, the trip takes 2 hours for the duck and 3 hours for the chicken, since the chicken lives 40 miles farther away than the duck. T

Question 906945: A duck and a chicken are walking to school. One way, the trip takes 2 hours for the duck and 3 hours for the chicken, since the chicken lives 40 miles farther away than the duck. The chicken travels 5 mph faster than the duck. Find their average rates of travel.
Found 2 solutions by josmiceli, richwmiller:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Average speed is ( total distance ) / ( total time )
Let = distance duck has to travel
= distance chicken has to travel
-----------------------------------------
Duck's rate of travel:

Chicken's rate of travel:

------------------
You are given that:

Multiply both sides by

-------------------
The duck's average rate is:

mi/hr
--------------------------
The chicken's average rate is:

mi/hr

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Such speedy educated fowl!
Just 5 mph walking is fast even for a human.
r*t=d
r*2=d
(r+5)*3=d+40
3r+15=2r+40
r=25 mph for the duck
Now that is power walking!
r+5=30 mph for the chicken.
2*25=50 miles for the duck
3*30=90 miles for the chicken

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