SOLUTION: Jane leaves her house and drives in a straight line at a speed of 25 mph. Her speed on the return trip is 35 mph. The trip back home takes 20 minutes less than the outbound trip. W

Question 906472: Jane leaves her house and drives in a straight line at a speed of 25 mph. Her speed on the return trip is 35 mph. The trip back home takes 20 minutes less than the outbound trip. What was Jane's total travel time in hours? Assume both trips are in a straight line. Give your final answer as a simplified fraction.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
25*t=35*(t+-20/60)
25*t=35*t+-700/60
25*t=35*t+-700/60
700/60=35+25*t
700/60=10*t
1.16666667=t
t=1.16666667

RELATED QUESTIONS
Jane leaves her house and drives in a straight line at a speed of 25 mph. Her speed on... (answered by richwmiller)

Jane leaves her house and drives in a straight line at a speed of 30 mph. Her speed on... (answered by richwmiller)

Jane leaves her house and drives in a straight line at a speed of 40 mph. Her speed on... (answered by richwmiller)

Jane leaves her house and drives in a straight line at a speed of 55 mph. Her speed on... (answered by jhaashok630,lwsshak3)

Please help ! Jane leaves her house and drives in a straight line at a speed of 50 mph.... (answered by KMST)

Jane leaves her house and drives in a straight line at a speed of 30 mph. Her speed on... (answered by josgarithmetic)

Jane leaves her house and drives in a straight line at a speed of 39 mph. Her speed on... (answered by richwmiller)

Jane leaves her house and drives in a straight line at a speed of 42 mph. Her speed on... (answered by josmiceli)

Jane leaves her house and drives in a straight line at a speed of 60 mph. Her speed on... (answered by richwmiller,MathLover1)