SOLUTION: Martha leaves home at 9:am, bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Marth?
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Question 90617: Martha leaves home at 9:am, bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Marth?
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Thanks Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website! let t=Martha's time ... John's time is 2 hr less ... John catches up when the distances are equal ... (rate)(time)=distance
24t=48(t-2) ... 24t=48t-96 ... -24t=-96 ... t=4 ... John catches up at 1:00 PM
