SOLUTION: Syed and Jenny are 18 km apartwith Syed behind Jenny. They begin to walk at the same time. If they walk in the same direction they meet after 6 hours. If they walk towards each oth

Question 905257: Syed and Jenny are 18 km apartwith Syed behind Jenny. They begin to walk at the same time. If they walk in the same direction they meet after 6 hours. If they walk towards each other they meet in 2 hours. Find their speed
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Syed and Jenny are 18 km apartwith Syed behind Jenny. They begin to walk at the same time. If they walk in the same direction they meet after 6 hours. If they walk towards each other they meet in 2 hours. Find their speed.
***
let x=Syed's speed
let y=Jenny's speed
speed walking in the same direction = x-y
speed walking toward each other = x+y
travel time*speed=distance
..
6(x-y)=18
2(x+y)=18
..
6x-6y=18
2x+2y=18
..
6x-6y=18
6x+6y=54
add
12x=72
x=6
2y=18-2x=6
y=3
Syed's speed=6 km/hr
Jenny's speed=3 km/hr
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