SOLUTION: Rachel is driving to an appointment. at her current speed she will be 11 minutes late and her destination is still 68 miles away. she increses her speed by 6 miles per hour and arr

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Question 904999: Rachel is driving to an appointment. at her current speed she will be 11 minutes late and her destination is still 68 miles away. she increses her speed by 6 miles per hour and arrives on time. what was her original speed?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
r original speed
68/r -68/(r+6) = 11/60 hr |Multiplying thru by r(r+6) so as all denominators = 1
68*6 = (11/60)r(r+6)
11r^2 +66r - 60*68*6 = 0 (Tossing out the negative solution for unit measure)
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1081476 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 44.2700174048471, -50.2700174048471. Here's your graph:

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