SOLUTION: Really need your help!
Height of a ball: If a ball is thrown directly upward with a velocity of 40 ft/s, its height (in feet) after t seconds is given by y = 40t - 16t^2. What is
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Question 904102: Really need your help!
Height of a ball: If a ball is thrown directly upward with a velocity of 40 ft/s, its height (in feet) after t seconds is given by y = 40t - 16t^2. What is the maximum height attained by the ball?
Found 2 solutions by richwmiller, josmiceli:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
25 ft after 1.2 seconds
-32t+40=0
t=40/32=5/4
40t - 16t^2
40*5/4 - 16*25/16
y=50-25=25 ft
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The given formula is a parabola with a vertex
that is a maximum. Here's a plot:
--------------------
When the parabola has the form:
, the x-coordinate of
the maximum is at:
At , the height is a maximum
ft
This matches the plot
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