SOLUTION: Billy leaves home walking to school at 1.7 m/s. His sister Sally is running a bit late and leaves home 8.5 minutes late going 4.2 m/s on her bike. How long will it take for Sally t

Question 903162: Billy leaves home walking to school at 1.7 m/s. His sister Sally is running a bit late and leaves home 8.5 minutes late going 4.2 m/s on her bike. How long will it take for Sally to catch up to billy? How far away from home will they be when she catches him?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Billy leaves home walking to school at 1.7 m/s. His sister Sally is running a bit late and leaves home 8.5 minutes late going 4.2 m/s on her bike. How long will it take for Sally to catch up to billy? How far away from home will they be when she catches him?
***
1.7 m/s=60*1.7=102 m/min (Billy's speed)
4.2 m/s=60*4.2=252 m/min (Sally's speed)
..
let x=Sally's travel time
x+8.5=Billy's travel time
distance=speed*travel time(same for both Sally ans Billy)
..
252x=102(x+8.5)
252x=102x+867
150x=867
x=5.78 min
252x=1456.56 m
How long will it take for Sally to catch up to billy? 5.78 min
How far away from home will they be when she catches him? 1456.56 m
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