SOLUTION: An object projected from a height of 48 ft with an initial velocity of 32 ft per sec after t seconds has height h= -16t^2+32t+48. Find the height of the object after 2 second.

SOLUTION: An object projected from a height of 48 ft with an initial velocity of 32 ft per sec after t seconds has height h= -16t^2+32t+48. Find the height of the object after 2 second.

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Question 902914: An object projected from a height of 48 ft with an initial velocity of 32 ft per sec after t seconds has height h= -16t^2+32t+48.
Find the height of the object after 2 second.

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
h= -16t^2+32t+48.
h(2) = -64 + 64 + 48 = 48ft
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