SOLUTION: Jake drives a tractor from one town to another, a distance of 130 kilometers. He drives 9 kilometers per hour faster on the return trip, cutting 1 hour off the time. How fast does

Question 902629: Jake drives a tractor from one town to another, a distance of 130 kilometers. He drives 9 kilometers per hour faster on the return trip, cutting 1 hour off the time. How fast does he drive each way?
Found 2 solutions by Jc0110, MathTherapy:
Answer by Jc0110(165) (Show Source): You can put this solution on YOUR website!
Let speed = v while time = t.

Depart trip: --> Equation 1
--> Equation 2 ... Substitute into Equation 3.
Return trip: --> Equation 3

or ... Substitute both and into Equation 2.
or
hours or hours
hours is acceptable, while hours is unacceptable because time cannot be in negative.
Substitute into Equation 1 and 3 for speed of depart trip and speed of return trip respectively.
------------------------------------------------------------------------
Depart trip:
Speed of depart trip, v=km per hour
Therefore, speed of depart trip is 30 km per hour.
Return trip:
Speed of return trip, v+9=
Speed of return trip, v+9=km per hour
Therefore, speed of return trip is 39 km per hour.
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!

Jake drives a tractor from one town to another, a distance of 130 kilometers. He drives 9 kilometers per hour faster on the return trip, cutting 1 hour off the time. How fast does he drive each way?

Let average speed during outbound trip be S
Then average speed during inbound trip is: S + 9
Time equation derived from this:
130(S + 9) = 130(S) + S(S + 9) -------- Multiplying by LCD, S(S + 9)

(S - 30)(S + 39) = 0
S, or average speed during outbound trip = km//h
Average speed during inbound trip: 30 + 9, or km/h
You can do the check!!
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