SOLUTION: A goods train left A for B at 3 pm at an average speed of 60 km/hr.at 6 pm an express train also had left A for B on a parallel track at an average speed of 90 km/hr. How far from

Question 902557: A goods train left A for B at 3 pm at an average speed of 60 km/hr.at 6 pm an express train also had left A for B on a parallel track at an average speed of 90 km/hr. How far from A, is the express train expected to overtake the goods train?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Goods train 60 km/h
Express 90 km/h
Goods train 03:00
Express 06:00
Difference in time= 03:00 => 3.00 hours
Goods train will have covered 180.00 km when Express starts
catch up distance= 180.00 km
catch up speed = 90 -60
catch up speed = 30 km/h
Catchup time = catchup distance/catch up speed
catch up time= 6
catch up time= 6.00 hours
They will meet at 03:00 AM
Express speed = 90 km/h
Time to catch up = 6 hours
D=Speed * time
D= 90 * 6
D= 540 miles
Express will catch up when it has traveled 540 miles

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