SOLUTION: Mitch can jog to Lynn's place in 12 minutes. Lynn can ride her bike to Mitch's place in 5 minutes. How many minutes will they meet if they start from their place at the same time?

Question 901672: Mitch can jog to Lynn's place in 12 minutes. Lynn can ride her bike to Mitch's place in 5 minutes. How many minutes will they meet if they start from their place at the same time?
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
This might work easier if viewed as a task completion problem instead of a travel uniform rates problem.

Think of the distance between Mitch and Lynn from the place of each as 1 job.
This way, Mitch does this job in 12 minutes and Lynn does this job in 5 minutes. If they start this job at the same time then when do they finish (like doing 1 job working together, when do they meet)?

Rates
Mitch, d/12
Lynn, d/5
Think of d=1, ONE FULL DISTANCE, like one whole job.

RT=1, rate time, 1 job or more generally, RT=D using D to stand for the single distance or a number of or fraction of the single distance.

TIME is the variable.
Let t = unknown time for Mitch and Lynn to do the job of the ONE distance.

Reminder, is in MINUTES.
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