SOLUTION: Steve begins walking towards kevins house at 3 mph. Kevin leaves his house at the same time and walks toward steves house on the same path at a rate of 2 mph. How long will it take

Question 900177: Steve begins walking towards kevins house at 3 mph. Kevin leaves his house at the same time and walks toward steves house on the same path at a rate of 2 mph. How long will it take before they meet if the distance between the houses is 4 miles
Found 2 solutions by richwmiller, lwsshak3:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
3t+2t=4
5t=4
t=4/5 hr
t= 48 minutes
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Steve begins walking towards kevins house at 3 mph. Kevin leaves his house at the same time and walks toward steves house on the same path at a rate of 2 mph. How long will it take before they meet if the distance between the houses is 4 miles
***
Steve and Kevins are approaching each other at a speed of 3+2=5 mph
travel time=distance/speed=4/5 hr
How long will it take before they meet=4/5 hr or 48 min
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