SOLUTION: A vehicle leaves a station at noon heading for a destination. an hour later a second vehicle traveling 10 mph faster leaves the same station. by 4:00 pm the first vehicle reaches i

Question 899744: A vehicle leaves a station at noon heading for a destination. an hour later a second vehicle traveling 10 mph faster leaves the same station. by 4:00 pm the first vehicle reaches it's destination, and the second is still 10 miles away. how fast is each vehicle?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Let speed of first vehicle be x
speed of second vehicle = (x+10)
Time traveled by first vehicle = 4 hours
Time traveled by second vehicle =3hours
D=rt
Distance traveled by first vehicle = 4x
distance traveled by second vehicle = 3(x+10)
They are 10 miles apart
4x-3(x+10)=10
4x-3x-30=10
x=30+10
x=40
speed of first vehicle be 40 mph
speed of second vehicle = (x+10)
= 50 mph
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