SOLUTION: A plane leaves an airport at 2 P.M. At 3 P.M., another plane leaves the same airport traveling in the same direction at a speed that is 150 mph faster than that of the first plane.

Question 898564: A plane leaves an airport at 2 P.M. At 3 P.M., another plane leaves the same airport traveling in the same direction at a speed that is 150 mph faster than that of the first plane. Four hours after the first plane takes off, the second plane is 300 mi ahead of the first plane. How far did the second plane travel?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = the speed of the 1st plane
= the speed of the 2nd plane
--------------------------------------
From 2 PM to 3 PM is hr
The 1st plane has a head start of:

-----------------
Start a stop watch when the 2nd plane leaves
at 3 PM
-----------------
hrs after the 1st plane takes off will be
hrs on the stop watch
---------------------------------
Let = distance 2nd plane has traveled
when stopwatch reads hrs
= distance 1st plane
has traveled in that time
--------------------------
Equation for 1st plane:
(1)
(1)
(1)
--------------
Equation for 2nd plane:
(2)
-----------------------
(2)
Substitute (1) into (2)
(2)
(2)
and

-------------------
The 2nd plane traveled:
(1)
(1)
(1)
(1) mi
----------------------
check answer:
(1)
(1)
(1)
and
(2)
(2)
(2)
(2)
OK

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