SOLUTION: Please help me solve this problem: Two hikers start from the same point and hike in opposite directions around a lake whose shoreline is 11 mi long. One hiker walks 0.5 mph faster

Question 898520: Please help me solve this problem: Two hikers start from the same point and hike in opposite directions around a lake whose shoreline is 11 mi long. One hiker walks 0.5 mph faster than the other hiker. How fast did each hiker walk if they meet in 2 h?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The sum of their distances for 2 hours was 11 miles.

RT=D and you have two of these terms for RT.

r = one of their speeds;

You know what to do.

Solution steps could vary, but one might choose:

Continue this until finished........
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Please help me solve this problem: Two hikers start from the same point and hike in opposite directions around a lake whose shoreline is 11 mi long. One hiker walks 0.5 mph faster than the other hiker. How fast did each hiker walk if they meet in 2 h?

Let speed of slower hiker be S
Then speed of faster hiker is: S + .5
Since their respective distances sum to 11 miles, and they met in 2 hours, then we get:
2S + 2(S + .5) = 11
2S + 2S + 1 = 11
4S = 11 � 1
4S = 10
S, or speed of slower hiker = , or mph
Faster hiker�s speed: 2.5 + .5, or mph
You can do the check!!
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