SOLUTION: Traveling with a current, a rower travels 1hr12min before turning around. Traveling against the current, it takes the rower 1hr48min to return to the starting point. The rower can

Question 891654: Traveling with a current, a rower travels 1hr12min before turning around. Traveling against the current, it takes the rower 1hr48min to return to the starting point. The rower can travel 6mph in water with no current. How fast is the current?
Answer by LinnW(1048) (Show Source): You can put this solution on YOUR website!
Set c = the speed of the current
Set d = distance traveled
(6 + c)*(1hr12min)= d
(6 - c)*(1hr48min)=d
***********
(6 + c)*(72min)= d
(6 - c)*(108min)= d
So (6 + c)*(72)= (6 - c)*(108)
432 + 72c = 648 - 108c
add 108c to each side
432 + 180c = 648
add -432 to each side
180c = 216
divide 180 by each side
c = 216/180
c = 1.2 mph
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