SOLUTION: Jay jay rode his bicycle against the wind for 1 hour and traveled 15 km. then he traveled back the same distance with the wind in 36 minutes, what was the rate of the wind?

Question 890301: Jay jay rode his bicycle against the wind for 1 hour and traveled 15 km. then he traveled back the same distance with the wind in 36 minutes, what was the rate of the wind?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Jay jay rode his bicycle against the wind for 1 hour and traveled 15 km.
then he traveled back the same distance with the wind in 36 minutes,
what was the rate of the wind?
:
Change 36 to hrs, 36/60 = .6 hrs
:
Let b = bike speed in still air
let w = rate of the the wind
then
(b-w) = effective speed against the wind
(b+w) = effective speed with the wind
:
Write a distance equation for each way, dist = time * speed
1(b-w) = 15
b = w + 15
and
.6(b+w) = 15
replace b = (w+15)
.6((w+15)+ w) = 15
.6(2w+15) = 15
1.2w + 9 = 15
1.2w = 15 - 9
1.2w = 6
w = 6/1.2
w = 5 km/h is the wind

RELATED QUESTIONS
Hi this my question: jay rode his bike at least 45 miles each week. jay rode his bike a... (answered by josmiceli)

john is riding his bike at 15 km against the wind. it takes him 1 hour to complete is... (answered by solver91311)

David rode his bike east at 20 mi/hr for 36 minutes with a tailwind. He then turned... (answered by stanbon,ikleyn,Alan3354)

Bill walks 6.25 km in 1 hour and 15 minutes, then runs 9 km in 45 minutes. What is the... (answered by Alan3354)

Jay bell made a recent business trip to Iowa, a distance of 450 miles, which required him (answered by mananth)

This is an Algebra 1 question: David rode his bike east at 20 mi/hr for 36 min with a... (answered by josgarithmetic,ikleyn,Alan3354)

he traveled 45 miles in those 2 hours with a current of 10 mph flowing in the opposite... (answered by lynnlo)

Flying with the wind, a plane traveled 510 miles in 3 hours. Flying against the wind, the (answered by josmiceli)

Macmac and Jay traveled at the same time at the rate of 20 m/min, from the same point on... (answered by greenestamps)