SOLUTION: Two sailboats, one averaging 20 miles per hour and the other 18 miles per hour, start at the same place and follow the same course. The slower boat arrives at the end of the course

Question 887428: Two sailboats, one averaging 20 miles per hour and the other 18 miles per hour, start at the same place and follow the same course. The slower boat arrives at the end of the course 1/6 of an hour after the faster sailboat. How far did each boat travel?
20x=18/x+1/6
I attempted to set up the chart like this. I'm not sure how to set up the equation.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Two sailboats, one averaging 20 miles per hour and the other 18 miles per hour, start at the same place and follow the same course. The slower boat arrives at the end of the course 1/6 of an hour after the faster sailboat. How far did each boat travel?
20x=18/x+1/6
I attempted to set up the chart like this. I'm not sure how to set up the equation.
=================
d = the distance
d = r*t
t = d/r
---
d/20 = d/18 - 1/6
Multiply by 180 to eliminate fractions
9d = 10d - 30
d = 30 miles

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