SOLUTION: On a pleasure trip, Bells drive their car a distance of 150 km at a rate of 30 kph faster than the rate they drive their boat a distance of 50 km. If the total time of the trip is

Question 884705: On a pleasure trip, Bells drive their car a distance of 150 km at a rate of 30 kph faster than the rate they drive their boat a distance of 50 km. If the total time of the trip is 5 � hours, how fast do they drive each vehicle? (How to solve this using 1 Variable only? PLEASE? )
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
|Multiplying thru by b(b+30) so as all denominators = 1
150b + 50(b+30) = 5.5b(b + 30)
5.5b^2 -35b -1500 = 0 (Tossing out the negative solution for unit measure)
b = 20kph and car is 50kph

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=34225 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 20, -13.6363636363636. Here's your graph:

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