SOLUTION: An object is launched upward at 45 ft/sec from a platform that is 40 feet high. What is the object's maximum height if the equation of height (h) in terms of time (t) of the object
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Question 881709: An object is launched upward at 45 ft/sec from a platform that is 40 feet high. What is the object's maximum height if the equation of height (h) in terms of time (t) of the object is given by h(t) = -16t2 + 45t + 40?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
4585/64 =71.640625 ft at 45/32 =1.40625 seconds
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