SOLUTION: Chris runs at 8 m/sec and Randy runs at a rate of 10 m/sec. If chis has a 10 second head start when will randy catch up to Chris (if ever)? Please help I've been struggling over th

Question 878772: Chris runs at 8 m/sec and Randy runs at a rate of 10 m/sec. If chis has a 10 second head start when will randy catch up to Chris (if ever)? Please help I've been struggling over this for hours I learned how to solve these types of problems months ago but I can't remember how to even set it up!
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
R*T=D, rate unit is meters per second.

Let t = time that Randy runs, which is 10 seconds less than the time Chris runs. Chris going slower, needs less time than than Randy.

d is some unknown distance which Chris and Randy each run.

________________speed_______time______distance
Chris___________8___________t+10______8(t+10)
Randy___________10___________t________10t

Again, their distances are equal when Randy meets Chris.
;
Solve for t, time in seconds.
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