SOLUTION: An arrow is shot vertically upward from a platform 10 ft high at a rate of 185 ft per sec. When will the arrow hit the ground? Use the formula: h=16t^2+vt+h. (round off answer to t

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Question 862633: An arrow is shot vertically upward from a platform 10 ft high at a rate of 185 ft per sec. When will the arrow hit the ground? Use the formula: h=16t^2+vt+h. (round off answer to the nearest tenth. Find seconds.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
h= -16t^2+185t+10, h = 0 when it hits the ground
16t^2+185t+10 = 0
t = 11.6sec (to nearest tenth)
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=34865 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: -0.0538036897701293, 11.6163036897701. Here's your graph:

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