SOLUTION: at noon mike bikes toward sues home at 12 mph and sue bikes toward mikes home at 8 mph when will they meet if their homes are 30 miles apart
Algebra.Com
Question 862099: at noon mike bikes toward sues home at 12 mph and sue bikes toward mikes home at 8 mph when will they meet if their homes are 30 miles apart
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
12t+8t=30
20t=30
t=1.5
They meet at 1:30 pm
sue rode 12 miles
mike rode 18 miles
RELATED QUESTIONS
at noon mike bikes toward sues home at 12 mph and sue bikes toward mikes home at 8 mph... (answered by josmiceli)
Gerry and Tony live 11km apart. Gerry leaves his home at 2 p.m. and bikes toward Tony's... (answered by josmiceli)
martha leaves home and travels toward school at 4 mph. At exactly the same time, Kristen... (answered by ankor@dixie-net.com)
Joy lives 466 miles from Max. At 8a.m., Joy starts driving toward Max's home at 60 mph.... (answered by robertb)
Justin starts at a point 26 miles from home and runs toward home at 6 mph. Rhonda starts... (answered by josmiceli)
Jack and Mark live 4 miles apart from each other on Baseline Road. At 6 pm, their moms... (answered by jorel1380)
At 8:00am Dave leaves his home on his moped, traveling east at 18 mph. At the same time... (answered by texttutoring)
At the same time, Sam and Fred who are 210 miles apart begin moving toward each other.... (answered by Alan3354)
ok, i'm a little stuck finding the equasion. the problem is:
At 1:00 P.M. Sue left her (answered by stanbon)