SOLUTION: The figure shows the elliptical orbit of Mercury, whose minimum distance to the Sun is 29 million miles and whose maximum distance to the Sun is 43 million miles. According to Kepl

Question 861458: The figure shows the elliptical orbit of Mercury, whose minimum distance to the Sun is 29 million miles and whose maximum distance to the Sun is 43 million miles. According to Kepler's laws, the average distance of a planet to the Sun is equal to half the length of the orbit's major axis. The average distance of Mercury to the Sun is million miles. (Enter only the number.)
I subtracted 43-29= 21.5 but I don't know if it is correct or not. Please Help!
Found 2 solutions by solver91311, richwmiller:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

The major axis of the orbital ellipse is the sum of the minimum distance plus the maximum distance. You need half of that number.

John

My calculator said it, I believe it, that settles it

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
You are very funny.
43-29= 21.5 is not correct and not even close.

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