SOLUTION: Train A is traveling 8km/hr faster than train B. Both trains start at the same time at opposite ends of a 50 km long track and are traveling towards each other. They meet after 17
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Question 85862This question is from textbook Basic Technical Mathematics
: Train A is traveling 8km/hr faster than train B. Both trains start at the same time at opposite ends of a 50 km long track and are traveling towards each other. They meet after 17 minutes of travel. What are the trains' speed of travel?
This question is from textbook Basic Technical Mathematics
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Train A is traveling 8 km/hr faster than train B. Both trains start at the same time at opposite ends of a 50 km long track and are traveling towards each other. They meet after 17 minutes of travel. What are the trains' speed of travel?
:
Let x = speed of Train B
Then
(x+8) = speed of Train A
:
We know when they meet, they will have traveled a total 50 km, both will have traveled for 17 min.
Change 17 min to hrs; 17/60 hrs
:
Distance = time * speed
:
Train A dist + Train B dist = 50
+ = 50
:
Get rid of the denominators, multiply equation by 60
17(x+8) + 17x = 60(50)
:
17x + 136 + 17x = 3000
:
34x = 3000 - 136
:
x = 2864/34
:
x = 84.2353 km/hr, speed of Train B
:
84.2353 + 8 = 92.2353 km/hr speed of train A
:
:
Check our solution
Train B dist: (17/60)*84.2353 = 23.867
Train A dist: (17/60)*82.2353 = 26.133
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Total distance of both trains = 50 km
:
Did this make sense to you?
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