SOLUTION: A plane leaves an airport and flies at 360mi/hr on a course of 103° 15' for 1hr and 33minutes. Then it changes course to 236°45' and flies for 48minutes. How far is it from the air
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Question 854744: A plane leaves an airport and flies at 360mi/hr on a course of 103° 15' for 1hr and 33minutes. Then it changes course to 236°45' and flies for 48minutes. How far is it from the airport? If it wished to return, what would be its course?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A plane leaves an airport and flies at 360mi/hr on a course of 103° 15' for 1hr and 33minutes. Then it changes course to 236°45' and flies for 48minutes. How far is it from the airport? If it wished to return, what would be its course?
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360 mi/hr = 6 mi/minute
103° 15' = 103.25°
236° 45' = 236.75°
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Label the start point A, then B & C
AB = 6*93 = 558 miles (side c)
BC = 6*48 = 288 miles (side a)
Angle at B = 46.5 degs
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Side b = distance from start
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Ude Law of Sines to find the heading back to A
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