SOLUTION: Two cyclists, 81 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 3 hours later, what is the speed (in mi/h) of t

Question 853205: Two cyclists, 81 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 3 hours later, what is the speed (in mi/h) of the faster cyclist?

Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
A + B = 81 (the total distance they'll travel)
A = 2B (One cycles 2 times as fast as the other)
Substitute the known value of A into the first equation.
2B + B = 81
3B = 81
Divide by 3 to find the distance B travels. 81/3 = 27
If B's distance is 27 miles, then A's distance is 54. 27+54 does equal 81.
If B travels 27 miles in 3 hours, how many miles per hour? 27/3 = ???
If A travels 54 miles in 3 hours, how many miles per hour? 54/3 = ???
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