SOLUTION: two friends live 2.1 mi apart along the same road. If they walk toward each other at rates that diff by 1/2 mph and meet 36mins later how fast was each person walking?

Question 844903: two friends live 2.1 mi apart along the same road. If they walk toward each other at rates that diff by 1/2 mph and meet 36mins later how fast was each person walking?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
two friends live 2.1 mi apart along the same road.
If they walk toward each other at rates that diff by 1/2 mph and meet 36mins later
how fast was each person walking?
:
Let w = walking speed of the slower guy
then
(w+.5) = walking speed of the faster guy
:
Since we a working in mph, change 36 min: 36/60 = .6 hrs
:
When they meet their total distances will equal 2.1 mi
:
Write a distance equation, dist = speed * time
.6w + .6(w+.5) = 2.1
.6w + .6w + .3 = 2.1
1.2w = 2.1 - .3
w = 1.8/1.2
w = 1.5 mph for the slow guy
and
2.0 mph for the speedster
:
:
Confirm this solution by finding the actual dist each walked
1.5*.6 = .9
2.0*.6 = 1.2
-------------
total: 2.1
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