SOLUTION: At 1:00 p.m. a car leaves St. Louis for Chicago, traveling at a constant speed of 65 mph. At 2:00 p.m. a truck leaves Chicago for St. Louis, traveling at a constant speed of 55 mph
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Question 841687: At 1:00 p.m. a car leaves St. Louis for Chicago, traveling at a constant speed of 65 mph. At 2:00 p.m. a truck leaves Chicago for St. Louis, traveling at a constant speed of 55 mph. If it is a 305 mile drive between St. Louis and Chicago, at what time will the car and truck pass each other? Please let me know how to solve this problem as soon as possible.
Answer by josgarithmetic(39621) (Show Source): You can put this solution on YOUR website!
Analyze the description and fill a data table:
_______________________rate_________time___________distance
1PM St. L to Chgo______65 __________t+1_____________
2PM Chgo to St. L______55___________t_______________
They pass each other when the sum of their distances is 305 miles.
Understand, the "t+1" is not because of "1PM", but because of this car traveling for one hour longer than the 2PM departure car.
Use the travel equation R*T=D to determine expressions for the distances of each car.
_______________________rate_________time___________distance
1PM St. L to Chgo______65 __________t+1_____________65(t+1)
2PM Chgo to St. L______55___________t_______________55t
TOTAL______________________________________________305
The total distance gives the equation to solve for . You can figure the time in the day using , once you solve for it.
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