SOLUTION: A motorist traveled from city A to city B at an average speed of 50 mph. On the return trip, he left at 3:00pm and drove at an average rate of 60 mph, making the trip in 33 minutes

Question 83520: A motorist traveled from city A to city B at an average speed of 50 mph. On the return trip, he left at 3:00pm and drove at an average rate of 60 mph, making the trip in 33 minutes less time. What is the distance from city A to city B?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A motorist traveled from city A to city B at an average speed of 50 mph. On the return trip, he left at 3:00pm and drove at an average rate of 60 mph, making the trip in 33 minutes less time. What is the distance from city A to city B?
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A to B DATA:
Rate = 50 mph ; time = x hrs ; distance = rt = 50x miles
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B to A DATA:
Rate = 60 mph ; time = x-33/60 hrs ; distance = rt = 60(x-(33/60)) miles
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EQUATION:
distance = distance
50x = 60(x-(33/60))
50x = 60x - 33
10x = 33
x = 3.3 hrs
distance from A to B = 50(3.3) = 165 miles
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Cheers,
Stan H.
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