SOLUTION: Two fishing boats depart a harbor at the same time, one traveling east, the other south. The eastbound boat travels at a speed 7 mi/h faster than the southbound boat. After two hou

Question 831570: Two fishing boats depart a harbor at the same time, one traveling east, the other south. The eastbound boat travels at a speed 7 mi/h faster than the southbound boat. After two hours the boats are 34 mi apart. Find the speed of the southbound boat.

Found 3 solutions by josgarithmetic, MathTherapy, adamhen894:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Their departure point and their positions at any time form a right triangle with the right angle at the departure point. Pythagorean Theorem governs the triangle's sides.

Rate*Time=Distance, for any single direction.

East boat: (r+7)*2 miles
South boat: r*2 miles
Hypotenuse, distance between boats at 2 hours: 34 miles.
We do not know but want to find r, the speed of the southbound boat.

, just according to the triangle and Pythagorean Theorem.

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Discriminant: 14^2-4*2(-265)=2316=2*1158=2*2*579=2*2*3*193
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approximately, mph
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Two fishing boats depart a harbor at the same time, one traveling east, the other south. The eastbound boat travels at a speed 7 mi/h faster than the southbound boat. After two hours the boats are 34 mi apart. Find the speed of the southbound boat.

Equation, with S being speed of southbound boat:
Speed of southbound boat: mph
You can do the check!!
If you need a complete and detailed solution, let me know!!
Send comments, �thank-yous,� and inquiries to �D� at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously.
Answer by adamhen894(15)   (Show Source): You can put this solution on YOUR website!
for the eastbound boat,
distance:2(x+7) mile
speed:(x+7)mi/h
time: 2h
for the southbound boat,
distance: 2x mile
speed: x mi/h
time: 2 h
it's a right triangle problem, the hypotenuse is 34 miles apart.
now you can set up the equation using Pythagorean theorem,
(2x)^2+(2x+14)^2=34^2
using quadratic equation to solve for x,
you get x = 8
which is speed (mi/h) of southbound boat.
let me know if you have any questions, adamchen894@gmail.com
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